There are three tube lights, a TV and two fan's in Rakhi's living room. She finds that each tube light draws 40 W, the TV draws 60 W and each fan draws 80 W. On an average, each tubelight is kept ON for 8 hours, Tv for 6 hours and each fan for 20 hours everyday.
Find the cost of electricity consumed in the month of june, if the rate for electrical energy is Rs. 5.50 per kWh.
Answers
Given that, three tube lights, a TV and two fan's are in a living room.
Power consumed by one tube light = 40W
Power consumed by three tube light = 3 × 40W = 120W
Also given in question that, each tubelight is kept on for 8 hours.
So, Energy consumed by tube light = 8 × 120W = 960W ..........(1st equation)
Similarly,
Power consumed by one fan = 80W
Power consumed by two fan = 2 × 80W = 160W
Each fan is kept on for 20 hours. So,
Energy consumed by fan = 20 × 160W = 3200W .............(2nd equation)
Power consumed by T.V. = 60W
And T.V. is kept on for 6 hours.
Energy consumed by T.V. = 6 × 60W = 360W ............(3rd equation)
Consumption of energy in one day = (1st + 2nd + 3rd) equation
= (960 + 3200 + 360)W
= 4520 W
= 4.520 kW
We have to find the cost of electricity consumed in the month of June (30 days) if the rate for electrical energy is Rs. 5.50 per kWh.
= 4.520 × 30 × 5.50
= Rs. 745.8
Your answer is in the above image.