Math, asked by nshaji617, 6 months ago

There are to cities A and B at a distance of 100km and 240km respectively from
the third city C. City B is to the east of city C and city A is to the north of city C.

One has to reach from city A to city B or vice-versa via city C.

Residents of the two cities proposed a plan to construct a bypass route directly

connecting cities A and B.
city A
|
|
city B------------------- city c

a) Name the concept applied to find the length of bypass.

i) SAS theorem of similarity

ii) Basic Proportionality Theorem

iii) Area Theorem

iv) Pythagoras Theorem

b) The distance covered by the person to reach city B from city A or vice-versa

via the bypass route is?

i) 160km

ii) 270km

iii) 260km

iv) 340km

c) Distance a person had to travel to reach city B from city A before the bypass

was constructed?

i) 270km

ii) 340km

iii) 67600km

iv) 576km

d) Will the distance be more than the bypass route and by how much?

i) Yes,80km

ii) No

iii) Yes,600km

iv) No

Answers

Answered by luckyrajput804422
1

Answer:

the difference between a and b I s x kam answer is yes 80 km

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