Math, asked by rajvee4, 6 months ago

There are total 100 pens in the box, out of them 73 good, 12 slightly defective and 15 major defective. Kanu is a trader
who only buy good pens. But another trader Radha only reject the major defective pens. If randomly selected One pen
rom box. Find the probability of (i) it is acceptable to Kanu (ii) it is acceptable to Radha.​

Answers

Answered by shaikainter786
3

Answer:

i ) 0.73

ii) 0.85

explanation

total pens =100

good pens = 73

slightly defective pens = 12

major defective pens = 15

i) pens acceptable to kanu =good pens = 73

probability ( pens acceptable to kanu)

= 73÷100 = 0.73

ii) pens acceptable to radha = total pens - major defective pens = ( 100 - 15 = 85)

probability ( pens acceptable to radha )

= 85÷100 = 0.85

Answered by ra9nvishsh
0

Answer:

0.73 and 0.85

Step-by-step explanation:

Total no. of trial = 100

i) 0.73

ii) 0.85

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