Question

There are totally Rs.56 in a box in the denominations 50 paise coins, Rs.1 coins, Rs.2 coins. If 50 paise coins are four times Rs.1 coins and Rs.2 coins are half the number of Rs.1 coins, find the number of coins of each denominations​

Answer 1

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Let,

$50 \: paisa \: coin \: ⇒ \: x \\ 25 \: paisa \: coin \: ⇒ \frac{x}{2} \\ 1 \: rupee \: coin \: ⇒ \frac{x}{4}$

ACCORDING TO QUESTION CONDITION :-

$⇒ \: \: \: \: \: \: (\frac{1}{2} x \: + \: \frac{1}{4} (\frac{x}{2}) \: + \: 1( \frac{x}{4} ) = 56 \\</p><p>⇒ \: \: \frac{4x + x + 2x}{8} = 56 \\</p><p>⇒ \: \: 7x = 56 \times 8 \\</p><p>⇒ \: \: x = \frac{56 \times 8}{7 } \\</p><p> ⇒ \: \: x = 8 \times 8 \\</p><p>⇒ \: \: x = 64$