Math, asked by uditeshwar, 8 months ago

there are tow alloys A and B .Alloy A contains iron copper and zinc and alloy B contains iron and tin .Both alloys contains 60% of iron. Now both alloys A and B are mixed to form alloy C .The percentage of tin in the third alloy is half of that of iron in it .The ration of percentage of copper and zinc in alloy A is 3:1 .Find the ratio of quantities of copper in alloy A and tin in alloy B which are mixed to form the third alloy c a)1:3 b)1:8 c)1:4 d)can't be determined

Answers

Answered by satwikasunkara
1

Answer:

Option a) is correct

1:3

Step-by-step explanation:

Answered by nitishy969020
0

Answer:

I don't understand division please post me again

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