Question

There are two alloys made up of copper and aluminium. In the first alloy copper is half as much as aluminium and in the second alloy copper is thrice as much as aluminium. How many times the second alloy must be mixed with first alloy to get the new alloy in which copper is twice as much as aluminium

Answer 1

Answer: 4

Explanation,

first alloy second alloy

C Al C Al

Required alloy

C Al

2 1

Thus, Copper in first alloy = 1/3

copper in second alloy = 3/4

copper in required alloy =2/3

Answer 2

Answer:

Half $(\frac{1}{2})$  times the second alloy must be mixed with first alloy to get the new alloy in which copper is twice as much as aluminum.

Explanation:

Given two alloys made of copper and aluminum.

Let copper be represented as C and aluminum as A.

In first alloy copper is half of aluminum.

$C=\frac{A}{2}$  ......(1)

Ratio of copper to aluminum is $(\frac{C}{A})_{1} =\frac{1}{2}$

In second alloy copper is thrice as aluminum.

$C=3A$ ..........(2)

Ratio of copper to aluminum is $(\frac{C}{A})_{2} =3$

How many time second alloy should be mixed with first such that copper is twice of aluminum in the third alloy.

We need $C=2A$

Ratio of copper to aluminum is $\frac{C}{A}=2$

$\frac{C}{A}=(\frac{C}{A})_{1} +m*(\frac{C}{A})_{2}$

$2=\frac{1}{2}+3*m$

$2-\frac{1}{2} =3m$

$\frac{4-1}{2} =3m$

$\frac{3}{2}=3m$

$m=\frac{1}{2}$

To get the new alloy in which copper is twice as much as aluminum we mix half of the second alloy with first alloy.

To know more about alloys go to the following link

brainly.in/question/12616771

To know more about mixing of alloy go to the following link

https://brainly.in/question/40719499

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