Question

There are two bags 1 and 2 bag 1 contain 3 red and 5 black ball and bag 2 contain 4 red and 3 black ball one ball is transferred randomly from bag 1 to bag 2 and then a ball is drawn randomly from bag 2 if the ball so drawn is found to be black in colour then find the probability that the transferred ball is also black

Answer 1

Step-by-step explanation:

question is confused

Answer 2

Answer:

P(black in bag II/ transferred ball is also black) = 20/64/(9/64+20/64) = 20/29

Answer: 20/29

Step-by-step explanation:

Bag I: total balls,

P(black ball/bag I)=5/8

P(red ball /bag I) = 3/8

After transferring one ball from bag I to bag II:

case 1: ball chosen is red , no of balls in bag II is 5 red and 3 black =8 balls

if a ball is chosen from bag II ,now

P(Black / bag II) =3/8 x 3/8=9/64

case 2: ball chosen from bag I is black and transferred to bag II

on choosing a ball now:( out of 4 red+ 4 black = 8 balls)

P(black /bag II) = 5/8 x 4/8=20/64

P(black in bag II/ transferred ball is also black) = 20/64/(9/64+20/64) = 20/29

Answer: 20/29