There are two bags A and B. A contains 4 white and 2 black balls and B contains
2 white and 4 black balls. One of the two bags is selected at random and two balls
are drawn from it without replacement.
Find the probability that the balls drawn are 1 black and I white.
Given that I black and 1 white balls are drawn, what is the probability that
bag A was used to draw the balls?
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Answer:
The probability that the balls are drawn from bag Y is
17
9
.
Step-by-step explanation:
Bag X contains 4 white balls and 2 black balls , Bag Y contains 3 white balls and 3 black balls.
Number of ways of selecting 1 white ball and 1 black ball from bag X is 4×2=8 ways.
Number of ways of selecting 1 white ball and 1 black ball from bag Y is 3×3=9 ways.
Total number of ways is 8+9=17.
The probability that the balls are drawn from bag Y is
17
9
.
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