There are two bags of rice. One Back weighs 76 whole 5 by 6 kg and other weighs 42 whole 2 by 3 kg if 5 by 7 of the total wheight is sold find the weight of the remaining rice.
Answers
Answer:
Weight of the first bag is 76 5/6
Weight of the second bag is 42 2/3
W e i g h t space o f space f i r s t space b a g equals 76 space 5 over 6 equals 461 over 6
W e i g h t space o f space s e c o n d space b a g equals 42 space 2 over 3 equals 128 over 3
T o t a l space w e i g h t space o f space t h e space t w o space b a g s equals 461 over 6 plus 128 over 3 equals fraction numerator 461 plus 256 over denominator 6 end fraction equals 717 over 6
5 over 7 space o f space t h e space t o t a l space w e i g h t equals 5 over 7 cross times 717 over 6 equals 1195 over 14
W e i g h t space o f space t h e space r e m a i n i n g space r i c e space equals 239 over 2 minus 1195 over 14 equals 239 over 7
Step-by-step explanation:
Weight of 1st Bag of rice= 76⅚
Weight of 2nd Bag of rice=42 whole 5/7 kg
Total Weight of both bags=
=>76⅚+42 whole 5/7
=462/6 + 299/7
=3234/42 + 1794/42
=5028/42
=838/7
=119 whole 5/7 kg
Amount of rice sold= 5/7 kg of Total
= 5/7 kg of 119 whole 5/7 kg
= 5/7 kg of 838/7
= 4190/49 kg
= 85 whole 25/42 kg
Amount of rice left=119 whole 5/7 kg-85 whole 25/42kg
=838/7 - 4190/49
=5866/49 - 4190/49
=1676/49
=34 whole 10/49 (Answer)
Here's the step by step explanation.
I hope it helps.