Question

There are two bags of rice. one bags weights 76 whole 5/6 kg and other weights 42 whole 2/3 kg. if 5/7 of the total weight is sold, find the weight of the remaining rice​

Answer 1

The weight of the remaining rice​ is $34\frac{1}{7}\ kg$.

Step-by-step explanation:

The weight of the first rice bag is, $76\frac{5}{6}\ kg=\frac{461}{6}\ kg$.

The weight of the second rice bag is, $42\frac{2}{3}\ kg=\frac{128}{3}\ kg$.

Compute the total weight as follows:

$Total\ weight=\frac{461}{6}+\frac{128}{3}=\frac{717}{6}\ kg$

It is provided that $\frac{5}{7}$ of the total weight is sold.

Remaining proportion of rice is, $1-\frac{5}{7}=\frac{7-5}{7}=\frac{2}{7}$.

Compute the value $\frac{2}{7}$ of the total weight of rice as follows:

$Remaining=\frac{2}{7}\times \frac{717}{6}=\frac{239}{7}=34\frac{1}{7}\ kg$

Thus, the weight of the remaining rice​ is $34\frac{1}{7}\ kg$.

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https://brainly.in/question/4496323

Answer 2

Answer:

the answer of this question is 34 whole 1/7