There are two bags, one of which contains 5 red and 7 white balls and the other 3 red and 12 white balls. A ball is to be drawn from one or other of the two bags ; find the chances of drawing a red ball.
Answers
first bag= 1/2×5/12
Second bag= 1/2×3/15
Total =( 1/2 ×5/12 + 1/2 × 3/15 )
=37/120
Answer:
The given question is of probability concept in Mathematics. Let us see how to solve it.
Step-by-step explanation:
Given: Two bags, one of which contains 5 red and 7 white balls. the other contains 3 red and 12 whit balls instead.
To Find: The probability of drawing a red ball from any of the two bags.
Now, we have two bags.
No. of total balls in the first bag = 5 red + 7 white balls = 12 balls in total
No. of total balls in the second bag = 3 red + 12 white balls = 15 balls in total.
Now, probability of finding ball :
= No. of favorable outcomes / Total no. of outcomes
Hence, probability of finding a red ball from 1st bag:
= 5/(5 + 7)
= 5/12
Similarly, probability of finding a red ball from 2nd bag:
= 3/(3 + 12)
= 3/15
= 1/5
Now, either first can happen or second because we only have to draw out one red ball. Therefore.
Total probability = 5/12 + 1/5
= 37/60
Hence, the probability of drawing a red ball is 37/60.