There are two boats together either side of lighthouse 200ft high. The angles of depression of the boats from the top of the lighthouse are 40° and 50° respectively.If the boats and lighthouse are in one straight line, calculate the distance between the boats.
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Figure is in the attachment.
Let A and B be the position of two boats (figure)
Let PM be the lighthouse such that PM =100m
Let AM =x and BM =y
In ΔAPM,
PM
AM
=cot30
∘
⇒
100
x
=
3
⇒x=100
3
m
Similarly in Δ BPM,
PM
BM
=cot45
∘
⇒
100
y
=1⇒y=100m
∴ Required distance, AB=x+y
=100
3
+100=100(
3
+1)m=273.2m
Hope it helps.
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