Math, asked by gundarakesh143, 18 days ago

There are two bowls. One carries 75 red marbles and 25 blue marbles, and the other has 50 red marbles and 50 blue marbles. If both bowls have equal possibilities of selection and the selected marble is red, then what is the probability that the marble was picked from the first bowl? ​

Answers

Answered by NishaanthA
0

Answer:

Step-by-step explanation:

Let P(R) be the probability of picking a red marble.

P(R) = P(B1) * P(B1 | J1) + P(B2) * P(B2 | J2)

If we do not reshuffle any balls. Then

P(R) = ((1 / 2) * 1) + ((1 / 2) * 0) = 0.5

But, If we decrease the number of red balls in box B1 and increase the number of red balls in box B2 then the probability of getting a red ball will be maximized.

Therefore, let us take 49 red marbles from B1 to B2 then there will be 1 red ball in B1 and 99 balls in B2 out of which 49 are red and 50 of them are blue in the second jar.

Then

P (R) = ((1 / 2) * (1 / 1)) + ((1 / 2) * (49 / 99)) = 0.747474

Hence,

the maximum probability of choosing a red ball is 0.747474

Answered by The2346
0

Answer:

The answer will be .74

Step-by-step explanation:

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