there are two bunches of banana. the first bunch has one third bananas more than the second bunch. if the second bunch has 3 banana less than the first bunch, how many bananas has the first bunch?
Answers
Solution :-
Let us assume that, the second bunch has x banana .
so,
→ First bunch has = x + (x/3) = (4x/3) banana .
A/q,
→ (4x/3) - x = 3
→ (4x - 3x)/3 = 3
→ x/3 = 3
→ x = 9 .
then,
→ First bunch has = (4x/3) = (4 * 9)/3 = 12 bananas (Ans.)
Hence, First bunch has total 12 bananas .
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Given : there are two bunches of banana.
the first bunch has one third bananas more than the second bunch.
if the second bunch has 3 banana less than the first bunch,
To Find : how many bananas has the first bunch?
Solution:
Let say first bunch = x
second bunch has 3 banana less than the first bunch
=> second bunch = x - 3
first bunch has one third bananas more than the second bunch.
=> x = (x - 3) + (1/3)(x - 3)
=> x = (4/3)(x - 3)
=> 3x = 4x - 12
=> x = 12
Hence there are 12 bananas in first bunch,
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