Question

there are two charges +2mC and -3 mC.The ratio of forces acting on them will be

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Answer 1

the force on +2 mc charge by -3 mc charge

F=Kq1q2 / r²

F=K6×10^-6/r2

the force on -3 mc charge by +2 mc charge

F=Kq1q2 / r²

F=K6×10^-6/r2

as F1 and F2 are equal the ratio is 1:1

I hope this helps ( ╹▽╹ )