There are two circular portions on two sides of a square lawn of side 58m. The centre of each circular portion is the portion is the point of intersection of the diagonals of the square lawn.Find the area of the lawn in whole.
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Let ABCD be a square with side 58 metres
Let its diagonals intersect at O
Then OA=OB=OC=OD and
∠AOD=∠BOC=90
∘
With radius=
2
1
AC arcs have been drawn namely AED and CBF
∴Radius of each arc=
2
1
×diagonal
=
2
1
2
×58
=1.41×29=40.89metres.
58×58+2×[
7
22
×(40.89)
2
×
360
90
−
2
1
×(40.89)
2
90
∘
]
33.64+
7
11×(40.89)
2
−(40.89)
2
=(3364+2627.4−1671.9) sq metres
=4319.5 sq metres
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