Question

there are two common oxides of sulphur one of which contains 50 percent O2 by weight ,the other almost exactly 60 percent .the weights of sulphur which combine with 1 g of O2 (fixed)are in the ratio of​

Answer 1

Answer:

Explanation:

FIRST OXIDE SECOND OXIDE

Oxygen 50% 60%

sulphur(by diff) 50% 40%

In first oxide 50 parts by weight of oxygen combine with sulphur=50 parts

1 part by weight of oxygen will combine with sulphur=50/50=1

In second oxide 60 parts by weight of oxygen combine with sulphur=40 parts

1 part by weight of oxygen will combine with sulphur=40/60=2/3

Compare the weights of sulphur which combine with same weight of oxygen in both oxides

1:2/3

=3:2

Answer 2

Answer:

i know the answer my buddy , its 3 : 2

Explanation:

In the first oxide, the percentages of O and S are 50% and 50%, respectively.

Thus, 1 g of oxygen will combine with 1 g of sulphur.

In the second oxide, the percentages of O and S are 60% and 40%, respectively.

Thus, 1 g of oxygen will combine with  

3

2

​  

 g of sulphur.

The ratio of weights of sulphur which combine with 1 g of oxygen = 1:  

3

2

​  

 = 3:2.