there are two concentric circles with centre O and of radii 5cm and 3cm. From an external point P, tangents PA and PB are drawn to these circles. If AP = 12cm, find the length of BP.
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Answer:6cm
Step-by-step explanation:
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Join OA and OB
Triangle OAP and OBP are right angled triangle.
In Triangle OAP
AP= 12 cm , OA= 5 cm
OP2 = OA2 + AP2
= 52 + 122
=25 + 144 = 169
OP = 13 cm
In Triangle OBP
OP = 13 cm, OB= 3 cm.
OP2 = OB2 + BP2
OP2- OB2 = BP2
=132 - 32
=169 -9
= 160
BP = 4 root 10
Triangle OAP and OBP are right angled triangle.
In Triangle OAP
AP= 12 cm , OA= 5 cm
OP2 = OA2 + AP2
= 52 + 122
=25 + 144 = 169
OP = 13 cm
In Triangle OBP
OP = 13 cm, OB= 3 cm.
OP2 = OB2 + BP2
OP2- OB2 = BP2
=132 - 32
=169 -9
= 160
BP = 4 root 10
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