There are two concentric conducting shells the potential of outer shell id 10 v and inner shell is 15 v if outer shell is grounded then potential if inner shell is
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Let radius of outer sphere is R and radius of inner sphere is r. charge on outer sphere is Q and charge on inner sphere is q.
now, potential on outer sphere, V = kq/R + kQ/R = k(q + Q)/R = 10 volts ....(1)
potential on inner sphere , v = kq/r + kQ/R = 15 volts ....(2)
from equations (1) And (2),
kq/r - kq/R = 5
or, kq(1/r - 1/R) = 5......(3)
a/c to question, outer sphere is grounded .so, potential on outer sphere , V= 0
so, k(q + Q)/R = 0 => q = -Q
now potential on inner sphere , v = kq/r + kQ/R
= kq/r + k(-q)/R
= kq(1/r - 1/R)
from equation (3),
= 5
hence, potential on inner spherical shell is 5 volts.
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