Question

There are two conductor A and B having resistances 10 ohm and 20 ohm. When these are connected individually with a cell of voltage 2 volt then in which conductor resistant is more and why ?


There are two conductor A and B having resistances 10 ohm and 20 ohm. When these are connected individually with a cell of voltage 2 volt then in which conductor resistant is more and why ?​

Answer 1

Answer:

HERE'S YOUR ANSWER IN THE PHOTO

Answer 2

Answer:

The circuit current

I = 12/(10+20)

I = 12/30

I =0.4 Amps.

Power dissiparion in 10- ohm resistor

P1= I^2R1

P1 = 0.4 x0. 4 x10

P1= 1.6 watts

Power dissiparion in 20- ohm resistor

P2= I^2R2

P2 = 0.4 x0. 4 x20

P2= 3.2 watts

Explanation:

thanks