there are two containers containing gases, one at pressure 30 atm and volume 20 ml and the other at pressure 25 atm. what will be the volume of the container when two are mixed?
Answers
1st part: First of all we have to find out the no. of moles of gas present from the equation…
Given, P=2 atm, V=10 L, T=273 K, R=0.082 L-atm/mol*K, n=?????
Putting all the values in the above equation we get no. of moles , n=0.89 mole
2nd part: We have to find out the temp required from the given pressure…
Again, P=2.50 atm, V=10 L, R=0.082 L-atm/mol*K, n=0.89 mole, T=???????
Putting all the values in the above equation we get, T=342.5 K or, 69.5 degree C..
Thank you..
1st part: First of all we have to find out the no. of moles of gas present from the equation…
Given, P=2 atm, V=10 L, T=273 K, R=0.082 L-atm/mol*K, n=?????
Putting all the values in the above equation we get no. of moles , n=0.89 mole
2nd part: We have to find out the temp required from the given pressure…
Again, P=2.50 atm, V=10 L, R=0.082 L-atm/mol*K, n=0.89 mole, T=???????
Putting all the values in the above equation we get, T=342.5 K or, 69.5 degree C..
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