Question

There are two containers with one containing 4 red and 3 green balls and the other containing 3 blue balls and 4 green balls. One ball is drawn at random from each container. The probability that one of the balls is red and the other is blue will be ________

Answer 1

I hope this help you

Answer 2

Answer:

Probability that one of the balls is red and the other is blue = 12/49

Step-by-step explanation:

Number of red balls in first container = 4

Number of green balls in first container = 3

Total number of balls in first container = 4 + 3 = 7

Number of blue balls in second container = 3

Number of green balls in second container = 4

Total number of balls in second container = 4 + 3 = 7

So, Probability of drawing a red ball first = 4/7

Also, Probability of drawing a blue ball in second draw = 3/7

Now, probability that one of the balls is red and the other is blue = 4/7 × 3/7

   = 12/49