Question

There are two covers A and B each containing paper slips with natural numbers from 1 to 7 written on them. One slip isdrawn from each cover. Using them, a two digit number is formed with a number from A in the units place and the number from B in the tens place. How many such two digit numbers can be formed What is the probability that a two digit number so formed is even?​

Answer 1

Answer:

49

Step-by-step explanation:

$C_{7} ^{1}$×$C_{7} ^{1}$=$\frac{7!}{6!1!}$×$\frac{7!}{6!1!}$=7×7=49

Answer 2

Answer:

Step-by-step explanation:

Given

7 slips with number 1 to 7 is written on them

If we want to make a 2 digit number by choosing the digits on the slip

No of ways in which first chit for unit place can be chosen is $^{7}C_1=7$

No of ways in which second chit for tens place can be chosen is $^{7}C_1=6$

total no of ways is $=7\times 7=49$

Among 49 numbers 25 are odd 24 are even so probability of obtaining a even number is

$\frac{24}{49}$