There are two cross roads,each of width 4m ruñning at right angles and parallel to the sides of a square park of side 72m.find the area of the park.
Answers
Answered by
8
Answer:
Step-by-step explanation:
Each sides of the square park measure = 72 m
We know, area of square = s^2 or s x s ( s square)
= 72^2 or 72 X 72
= 5184 sq. m
Answered by
12
Answer:
70,000
Step-by-step explanation:
Area of the crossroads, is equal to the area of the shaded portion in the figure.
Area of the shaded portion
=Area of the rectangle EFGH + Area of the rectangle IJKL - Area of the square PQRS
Area of the rectangle EFGH
= length×breadth = 72×4 = 288sq.m
Area of the rectangle IJKL
= length×breath = 72×4 = 288sq.m
Area of square PQRS
= side×side = 4×4 = 16sq.m
The cost of paving tiles
= 560×125 = 70,000
Similar questions