Question

There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser
amount of material to make?

Answer 1

Answer:

We know that,

Total surface area of the cuboid = 2 (lh + bh + lb)

Total surface area of the cube = 6 (l)2

Total surface area of cuboid (a) = [2{(60) (40) + (40) (50) + (50) (60)}] cm²

$= [2(2400 + 2000 + 3000)] cm²$

$= (2 × 7400) cm²$

$= 14800 cm²$

Total surface area of cube (b) = 6 (50 cm)² = 15000 cm²

Thus, the cuboidal box (a) will require lesser amount of material.

Answer 2

Answer:

Please refer the attachment

:)