there are two electric burn mark 100 watt and 220 volt and mass 60 watt into 20 volt which one of them has higher resistance
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Given,
the first bulb is marked as 60 w,220 v
the second bulb is marked as 100 w,220 v
we know that P = V2 /R so, R = V2/P
in first bulb, R = (220)2/60 = 806.66 ohm
in second bulb,R = (220)2/100 = 484 ohm
hence, we can say that the first bulb has more resistance than second bulb
the first bulb is marked as 60 w,220 v
the second bulb is marked as 100 w,220 v
we know that P = V2 /R so, R = V2/P
in first bulb, R = (220)2/60 = 806.66 ohm
in second bulb,R = (220)2/100 = 484 ohm
hence, we can say that the first bulb has more resistance than second bulb
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