Question

there are two electric lamps M and N which are joined in a series having resistance 15 ohm and 20ohm . if the potential difference between two terminal of electric circuit is 220v find total resistence and electric current through the circuit .also find potential difference across two lamps seperetely​

Answer 1

Answer:

given,

r1 = 15π

R2= 20π

V = 220v

so, Re = r1 + R2 = 35 π [ in Series Re = r1 + r 2 + ...rn]

now, V = IR

=> I = V/R

=> I = 220/35 = 6.3A

so V1 = R1*I = 15 * 6.3 = 94v

V2 = R2*I = 20 * 6.3 = 126 v

Answer 2

Answer:Resistance of lamp m = 15Ω

Resistance of lamp n = 20Ω

Both are joined in series so, Req = R₁ + R₂

Req = 15Ω + 20Ω = 35Ω

Given, potential difference across the circuit = 220V

so, use Ohm's law,

V = iR

Current through circuit , i = 220/35 = 6.28 A

Now, potential difference across lamp m = Resistance of lamp × current

= 15Ω × 6.28A = 94.2V

Potential difference across lamp n = resistance of lamp n × current = 20 × 6.28A = 125.6 V

PLEASE MARK IT BRAINLIEST

PLZZ THANKS

Explanatio