Physics, asked by haneefrupalagudi, 6 hours ago

There are two entering currents in a node, I1 and I2 and two leaving currents I3 and I4. If I1= 2A, I3=3A and I4=4A, what is the value of I2?

Answers

Answered by neelaambika31

0

Answer:

5A

Explanation:

According to Kirchoff's law,

I1 + I2 = I3 + I4

2 + I2= 3 + 4

I2= 4+3-2

I2= 5A

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