There are two examination rooms A and B. if 10 students are sent from A to B, then the number of students in each room is the same. if 20 candidate are send from B to A, the number of students in A is double the number of students in B. The number of students in room A is?
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Let the no. of students in room A be x.
And those Room B be y
Now,
According to 1st condition,
x-10= y+10
→ x=y+20
According to the 2nd condition,
2(y-20) = x+20
2y-40= x +20
x= 2y-60
So from both equations we get
y+20= 2y-60
y= 80
So x= 80+20=100
I.e. no. of students in room A are 100.
And no. of students in room B are 80.
HOPE THIS HELPS YOU:)
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And those Room B be y
Now,
According to 1st condition,
x-10= y+10
→ x=y+20
According to the 2nd condition,
2(y-20) = x+20
2y-40= x +20
x= 2y-60
So from both equations we get
y+20= 2y-60
y= 80
So x= 80+20=100
I.e. no. of students in room A are 100.
And no. of students in room B are 80.
HOPE THIS HELPS YOU:)
★★★★★★★
harshmata3oybvei:
plz mark brainliest
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