there are two field one square and other rectangular have samecpermeter the length is 64 m. and breadth is 48 m of rectangular field whose area is greater and by how much
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perimeter of rectangle=2 (64+48)
=2 (112)=224
perimeter of square =4a=224
a=224/4
=56
area of square =a^2
=56^2
=3136
area of rectangle =lb
=64×48
=3072
Area of square is greater than area of rectangle by 64
=2 (112)=224
perimeter of square =4a=224
a=224/4
=56
area of square =a^2
=56^2
=3136
area of rectangle =lb
=64×48
=3072
Area of square is greater than area of rectangle by 64
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