Question

There are two forces F1 = 10 N and F2 = 20 N and the angle between them is 60°. Find F2-F1 and the angle alpha.​

Answer 1

Answer:

❣ ANSWER ❣

✡ ROCKY HERE ✌

F 1 = 10N and F2 = 20N

angle = 60°

F2 - F1

= 20 - 10

= 10 N

angle = 360 / 60

= 60 °

✴HAPPY TO HELP

Answer 2

jannatk0218

Answered

F1=10N and F2=20N and angle between them is 60° find f2-f1 and tan alpha

Answer:

tan alpha is root 3 f2 -f1 = 10N

.

Explanation:

Given:

f_1 = 10\ N.

f_2 = 20\ N.

Angle between \vec f_1 and \vec f_2, \theta=60^\circ.

Let \vec f_1 be along the positive x axis direction, then \vec f_2 is along the direction 60^\circ with respect to the positive x axis direction.

Assuming,

\hat i,\ \hat j are the unit vector along the positive x and y axis direction.

In unit vector notation, \vec f_1 and \vec f_2 are given as,

\vec f_1 = f_1\ \hat i=10\ \hat i\ N.\\\vec f_2 = f_2\cos(60^\circ)\ \hat i+f_2\sin(60^\circ)\ \hat j\\=20\cos(60^\circ)\ \hat i+20\sin(60^\circ)\ \hat j\\=(10\ \hat i\ +\ 17.32\ \hat j)\ N.

Therefore,

\vec f_2-\vec f_1=(10\hat i+17.32\hat j)-(10\hat i)=17.32\hat j\ N.

The resulting vector, \vec f_2-\vec f_1 is along the positive y axis direction, therefore its direction with respect to positive x axis is 90^\circ, if \alpha is the angle along the direction of \vec f_2-\vec f_1, then \alpha = 90^\circ.

which gives,

\tan\alpha = \tan90^\circ = \infty.