There are two heaps of 308 and 112 marbles respectively. Marbles of each heap an packed to have equal numbers in each packet. What is the greatest number of marble in cach packet?
Answers
The greatest number of marbles that can be packed into each packet with an equal number of marbles in each packet is 28 marbles.
To find the greatest number of marbles that can be packed into each packet with an equal number of marbles in each packet, we need to find the greatest common divisor (GCD) of the two given numbers: 308 and 112.
The GCD is the largest number that divides both of the given numbers evenly.
Let's calculate the GCD of 308 and 112:
List the divisors of 308: 1, 2, 4, 7, 14, 28, 49, 98, 154, 308.
List the divisors of 112: 1, 2, 4, 7, 8, 14, 28, 56, 112.
Common divisors of 308 and 112: 1, 2, 4, 7, 14, 28.
The greatest common divisor (GCD) of 308 and 112 is 28.
So, the greatest number of marbles that can be packed into each packet with an equal number of marbles in each packet is 28 marbles.
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