There are two identical jugs , A and B . Jug A is 3/7 full of water and Jug B is 96/11 full . What fraction of the capacity of a jug of water should be poured from B to A so that they both have the same volume of water ?
Answers
Answer:
x = 639y / 154
Step-by-step explanation:
We are given A and B are two jugs and have equal volume
Let say both have volume = y m³
The water in Jug A = 3/7 of total volume of A = 3y/7
The water in Jug B = 96/11 of total volume of B = 96y/11
Suppose x is subtracted form B and added in A such that volume to A and B become equal.
New volume of B = 96y/11 - x
New volume of A = 3y/7 + x
According to condition
New volume of B = New volume of A
Putting values we get
96y/11 - x = 3y/7 + x
⇒ x + x = 96y/11 - 3y/7 = ( 672y - 33y ) / 77 = 639y / 77
⇒ 2x = 639y / 77
⇒ x = 639y / 154
So
639y/154 is added in A to balance the volumes of A and B
and also 96/11 - 639/154 = 4.1493.. some
Which some my answer is correct
Answer:
23 / 154
Step-by-step explanation:
Find the total volume of water = 3/7 + 8/11 = 89/77
Divide the volume of water equally between Jug A & B.
Volume of water in Jug A or Jug B = (89/77) divided by 2
= 89/154
Volume of water poured = Original water in Jug B - Current water in Jug B
= 8/11 - 89/154 = 23/154