Math, asked by gangadharaswamy99, 5 months ago

There are two inlets A and B connected to
a tank. A and B can fill the tank in 16 h
and 10 h, respectively. If both the pipes
are opened alternately for 1 h, starting
from A, then how much time will the tank
take to be filled?​

Answers

Answered by kpzuhra40
0

Step-by-step explanation:

Part filled by A in 1 h = 116

Part filled by B in 1 h = 110

Part filled by (A+B) in 2 h

= 116+110=1380

Part filled by (A+ B) in 12 h = 6×1380=7880

Therefore, Remaining part = 1−7880=280=140

Total time taken by A to fill 140 part of the tank

= 140×16=25h

Therefore, Total time taken = (12+25)=1225h

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