There are two kinds of alloys of tin and copper. The first alloy contains tin and copper such that 93.33% of it is tin. In the second alloy, there is 86.66% tin. What weight of the first alloy (in kg) should be mixed with some weight of the second alloy so as to make a 50 kg mass containing 90% of tin?
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Given:
Alloy of copper and tin
Alloy 1,
Tin = 93.33 %
Alloy 2,
Tin = 86.66 %
To find:
The weight of the first alloy should be mixed with some weight of the second alloy so as to make a 50 kg mass containing 90% of tin.
Solution:
Consider x and y,
x - Weight of the first alloy
y - Weight of the second alloy
Here,
x + y = 50
Framing an equation,
14x / 15 + 13y / 15 = 90 / 100 * 50
14x + 13y = 675
Solving,
x + y =50
14x + 13y = 675
Solving for x,
We get,
x = 25 kg
Hence, 25 kg of the first alloy should be mixed with some weight of the second alloy so as to make a 50 kg mass containing 90% of tin.
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