Chemistry, asked by teddybaby5528, 1 year ago

There are two kinds of alloys of tin and copper. The first alloy contains tin and copper such that 93.33% of it is tin. In the second alloy, there is 86.66% tin. What weight of the first alloy (in kg) should be mixed with some weight of the second alloy so as to make a 50 kg mass containing 90% of tin?

Answers

Answered by topanswers
18

Given:

Alloy of copper and tin

Alloy 1,

Tin = 93.33 %

Alloy 2,

Tin = 86.66 %

To find:

The weight of the first alloy should be mixed with some weight of the second alloy so as to make a 50 kg mass containing 90% of tin.

Solution:

Consider x and y,

x - Weight of the first alloy

y - Weight of the second alloy

Here,

x + y = 50

Framing an equation,

14x / 15 + 13y / 15 = 90 / 100 * 50

14x + 13y = 675

Solving,

x + y =50

14x + 13y = 675

Solving for x,

We get,

x = 25 kg

Hence, 25 kg of the first alloy should be mixed with some weight of the second alloy so as to make a 50 kg mass containing 90% of tin.

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