There are two large parallel metallic plates S1 and S2 carrying surface charge densities l1 and l2 respectively (l1 > l2) placed at a distance d apart in vacuum. Find the work done by the electric field in moving a point charge q a distance a (a
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Answer:
Explanation:
electric field for area 1, 2 and 3 is E1, E2 and E3 respectively.
=> E1 = q1 + q2 / 2ε。
=> E2 = q1 - q2 / 2ε。
=> E3 = q1 + q2 / 2ε。
=> The value of potential Va is zero at point A because A point is on the S1.
∴Va = 0
=> The value of potential Vb at point B is (q1 + q2 / 2ε。) a
∴Vb = (q1 + q2 / 2ε。) a
work done by the electric field:
w = qΔV [but ΔV =Vb-Va]
∴ w = q*(Vb-Va)
= q*(a(q1 + q2 / 2ε。- 0)
= qa (q1 + q2 / 2ε。)
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