Question

there are two metal bars of lengths 120cm and 225cm.short bars of equal lengths are cut from the metal bars.findthe possible largest of each short bar.​

Answer 1

Answer:

Find the HCF of 120 and 225:

120 = 2³ × 3¹ × 5¹

225 = 3² × 5²

HCF (120 , 225) = 3¹ × 5¹ = 15

Therefore.,

The largest possible Length of each short bar = 15 cm

Answer 2

Answer:-

H.C.F of 120 & 225 = 15

Step-by-step explanation:-

Solution by Factorisation:

• The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120
• The factors of 225 are: 1, 3, 5, 9, 15, 25, 45, 75, 225

Then the greatest common factor is 15.

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