Question

there are two metal bars of lengths 72 cm and96 cm .both bars cut into small pieces of exactly equal lengths .find the largest possible length of each small piece.​

Answer 1

Answer:

Given:

There are two metal bars of lengths 72cm and 96cm.  

T  o find:

The largest possible length to cut them in equal parts.  

Solution:  

1) As per the need for the condition of the question we have to find the HCF of the given numbers.  

HCF[72,96] we will find it by the prime factorization  

72 = 2×2×2×3×3

96 = 2×2×2×2×2×3

so the HCF is 2×2×2×3 = 24  

2) If we cut the first bar of 24cm length then we get 3 bars of the same length and in the second we get 4 of the same length.  

The largest possible length to cut them in equal parts is 24 cm.

HOPE IT HELPS o(*°▽°*)o