There are two metal bars of lengths 72cm and 96cm . Short bars of equal length are cut from both metal bars . Find the largest possible length .Give Step by Step answer with explanation.
Answers
Given:
There are two metal bars of lengths 72cm and 96cm.
To find:
The largest possible length to cut them in equal parts.
Solution:
1) As per the need for the condition of the question we have to find the HCF of the given numbers.
HCF[72,96] we will find it by the prime factorization
- 72 = 2×2×2×3×3
- 96 = 2×2×2×2×2×3
so the HCF is 2×2×2×3 = 24
2) If we cut the first bar of 24cm length then we get 3 bars of the same length and in the second we get 4 of the same length.
The largest possible length to cut them in equal parts is 24 cm.
Answer:
24 cm
Step-by-step explanation:
2 metal bars of lengths = 72 CM and 96 CM
The largest possible length of each short bar = HCF
(Prime Factorisation method)
(you can also do with short division method or long division method)
HCF =
72 = 2x2x2x3x3
96 = 2x2x2x2x2x3
Common factors = 2x2x2x3 (2 and 3)
= 24
= So, the largest possible length of each short bar = 24 cm (answer)
(I think its helpful)