Math, asked by rcjaiyogeshwar859, 2 days ago

There are two numbers in the ratio 4:7 . If they differ by 63, what are the numbers

Answers

Answered by pj2285961

0

Answer:

217 and 124

hope it help

please mark brainlist answer

Answered by saquibnawaz2005

0

Answer:

Let the number be 4x and 7x.

ATP

7x - 4x = 63

3x = 63

x = 63/3

x = 21

Therefore, the numbers are 4x and 7x = 4(21) and 7(21) = 84 and 147.

Answer = 84 and 147.

Hope, it will help you.

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