Math, asked by muhammadsameem26, 7 months ago

There are two numbers sach that sum of numbers is 9 and sum of their squares is 41 . find there product​

Answers

Answered by abhi569
12

Answer:

20

Step-by-step explanation:

 Let the required numbers are a and b.

        Sum of squares = a^2 + b^2 = 41

According to the question :

⇒ a + b = 9

      Square on both sides:

⇒ ( a + b )^2 = 9^2

⇒ a^2 + b^2 + 2ab = 81

⇒ 41 + 2ab = 81

⇒ 2ab = 81 - 41

⇒ 2ab = 40

⇒ ab = 40/2 = 20

 Hence product of those two numbers is 20.

Answered by mailmenandini
4

Answer:

3 and 6 can be the numbers......

As,

5 + 4 = 9

(4)² + (5)² = 16 +25 = 41

And thus,

The product of these two numbers is...

5×4= 20 .....

This is your answer......

Hope this helps you....

Plzzz mark me as brainliest..... :-) :-)

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