Question

there are two numbers such that sum of 2x and 3y is 3 while sum of 5x and 7y is 5. what are the numbers?​

Answer 1

Answer:

2x+3y=3 --(1)

5x+7y=5 --(2)

now multiply (1) by 5 and (2) by 2

And subtract (2) from (1)

10x+15y=15

10x+14y=10

-----------------

( y = 5)

now put value of y in (1)

2x+3(5)=3

2x+15=3

2x=3-15

2x= -12

( x= -6)

Step-by-step explanation:

so x is -6 and y is 5

Answer 2

x = - 6  & y = 5  are two numbers such that  that sum of 2x and 3y is 3 while sum of 5x and 7y is 5.

Step-by-step explanation:

there are two numbers such that

sum of 2x and 3y is 3

=> 2x + 3y  =  3     Eq1

sum of 5x and 7y is 5

=> 5x  + 7y  = 5     Eq2

5 * Eq1  - 2 * Eq2

=>  5(2x + 3y) - 2( 5x  + 7y) = 5 * 3  - 2 * 5

=> 10x + 15y - 10x - 14y  = 15 - 10

=> y = 5

Putting y = 5 in Eq 1

=> 2x + 3(5) = 3

=> 2x + 15 = 3

=> 2x = -12

=> x = - 6

x = - 6  & y = 5  are two numbers such that  that sum of 2x and 3y is 3 while sum of 5x and 7y is 5.

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