Question

There are two numbers such that sum of the numbers is 10 and their difference is 4. find the difference of their squares

Answer 1

Answer:

40

Step-by-step explanation:

Let the two no. be X and Y

Given

X+Y=10

X-Y=4

We know

${x}^{2} - {y}^{2} \\ = (x + y)(x - y) \\ = 10 \times 4 \\ = 40$

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Answer 2

Answer:

Let the two numbers be a and b.

If a+b=10 and a-b=4. And difference of their squares is a2-b2.

As according to the formula, (a+b) (a-b) =a2-b2.

So, 10×4=a2-b2. Then a2-b2 =40. It is the right answer.

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