Question

There are two numbers such that sum of the numbers is 14 and the sum of their squares is 106. Find their product.

Answer 1

Answer:

The sum of two numbers is 14

Let x and (14-x) represent the two numbers

Question states

x^2 + (14-x)^2 = 106

solving for x

2x^2 -28x + 196 = 106

2x^2 -28x + 90 = 0

2(x^2 -14x + 45) = 0

factoring

(x-9)(x-5) = 0 Numbers are 5 and 9

CHECKING our Answer

25 + 81 = 106

Answer 2

Answer:

45

Step-by-step explanation:

x+y=14 x^2+y^2=106 xy=?

the 2 numbers are 5 and 9

5+9=14 25+81=106 5(9)=45