Question

there are two numbers such that sum of the numbers is 31 and their difference is 5 find the sum of their cubes​

Answer 1

Answer:

$sum \: of \: cubes = 8029$

Answer 2

Step-by-step explanation:

Let the no.s be x & y

x+y = 31

x-y = 5

On adding both eqn , we get :-

2x = 36

x = 18

Putting this value in 1st eqn :

18+y = 31

y = 13

TF ,

x³+y³ = (13)³+(18)³ = 8029