Question

There are two numbers such that sum of the numbers is 48 and their difference is 8. Find the difference of their squares. a. 383 b. 384 C. 393 d. 385
PLZ ANSWER THE CORRECT ANS ONLY​

Answer 1

let the numbers be x & y

x + y = 48

x - y = 8

$(x + y)(x - y) = 48 \times 8 \\ {x}^{2} - xy + xy - {y}^{2} = 384 \\ {x}^{2} - {y}^{2} = 384$

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