Question

There are two numbers such that sum of the numbers is 50 and the difference is 14 .Find the difference of their cubes.

Answer 1

There are two numbers such that sum of the numbers is 50 and the difference is 14 .Find the difference of their cubes.

let one number be x and oher be y 

now,

x + y = 50......[1]

so

y = 50 - x

x - y = 14 ................[2]

on adding 1 and 2 we get

2x = 64

x = 64/2

x = 32

since y = 50 - x

           = 50 -32

         = 18

so the numbers are 32 and 18

now 

difference of their cubes.

> 32³ - 18³

=> 32768 - 5832

= 26936

:)

Answer 2

Hello dear user!!! ✌️✌️


Here is your answer goes like this :


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Your question :

There are two numbers such that sum of the numbers is 50 and the difference is 14 .Find the difference of their cubes.


Answer :


Given,

Let the numbers be X and Y

X+Y+50-------------------equation(1)

and

X-Y=14


From equation (1) and (2),we get

X+Y=50
X-Y=14
__________
2X=64

X=32

Substitute 'X' value in equation (1),we get

X+Y=50

32+Y=50

Y=18

Therefore the two numbers are 32 and 18

The difference of their cubes is :

==>32³-18³

==>32768-5823

==>26936


Therefore the difference of their cubes is 26936


The answer has been explained....



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HAVE A GREAT DAY DEAR ✌️✌️



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