Question

There are two numbers such that sum of the numbers is 50 and the difference is 14. Find the difference of their cube?

Answer 1

Let the two numbers be x and you Respectively
According to problem
x+y=50
x=50-y-------(1)
x-y=14
x=14+y-------(2)
Therefore,
50-y=14+y
50-14=y+y
36=2y
y=36/2=18
Since x+y=50
Put the value of y
x+18=50
x=50-18=32
Now, cube of 32=1024
And,cube of 18=324
Their difference=
1024 - 324 =700

Answer 2

Answer:

⇒ x - y = 26,936

Step-by-step explanation:

Let one number be 'x' & second number be 'y'

Now , Given that ;

=> x + y = 50 (i)

And,

=> x - y = 14 (ii)

Then ,

⇒x = 50 - y _________from (i)

Substituting the value of x in (ii), we get ;

⇒50 - y - y = 14

⇒50 - 2y = 14

⇒ - 2y = 14 - 50

⇒ - 2y = -36

⇒ y = 36/2 = 18

Putting value of y in (i), we get ;

⇒x + y = 50

⇒x + 18 = 50

⇒x = 50 - 18

⇒x = 32

Now , we have ;

x = 32 & y = 18.

Now , finding cubes ;

⇒x = 32 × 32 × 32 = 32,768

⇒y = 18 × 18 × 18 = 5,832

Now , find the difference between x & y ;

⇒x - y = 32,768 - 5,832

∴ x - y = 26,936

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