there are two numbers such that the product of the number is 45 and the difference is 12 find the sum and difference of their cubes
Answers
Answered by
6
Step-by-step explanation:
let the numbers be x and y respectively,
xy=45----1
x-y=12-----2
let x=12+y----3
substitute 3 in 1
we get (12+y)y=45 we get
12y +y^2 -45=0
solve this u will get the answer
Hope this helps you cheers
Answered by
0
Answer: 3, 15
Step-by-step explanation:
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