Math, asked by tanushajain040507, 6 months ago

There are two numbers such that the sum of the numbers is 48 and their difference is 8. Find the difference of their squares.
pls give answer quick.
I will mark as BRAINLIEST ​

Answers

Answered by CONFUSED1234
4

Answer:

x+y=48

x-y=8    ->    x=y+8

x+y=48    ->    y+8+y=48    ->    2y = 40    ->    y=20, x=28

Step-by-step explanation:

Answered by Dia095
7

Answer:

y=20, x=28

Step-by-step explanation:

x+y=48

x-y=8 -> x=y+8

x+y=48

-> y+8+y=48

-> 2y = 40

-> y=20,

x=28

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